1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Centripetal Acceleration.

  1. Feb 28, 2015 #1
    Since F=mv2/r. Does that mean the force required for centripetal acceleration is inversely proportional to the radius? If radius is more the lesser centripetal force is required, is this correct?
     
  2. jcsd
  3. Feb 28, 2015 #2

    Bystander

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    What's "v2?"
     
  4. Feb 28, 2015 #3

    Suraj M

    User Avatar
    Gold Member

    That's if v is constant,
    In most situations, ##\omega##(angular velocity) is constant, so try expressing centripetal force in terms of ##\omega##
     
  5. Mar 1, 2015 #4
    Now there are 2 formulas for centripetal acceleration. 1. F= mv2/r. So in this formula we know that as radius increases the speed or velocity increases. So the term v2/r remains constant. So how can we prove from this formula that the Centripetal force is more if the radius is more.

    But if we take the formula 2. F=mω2r. we can easily prove that as the radius increases the Centripetal force required increases. But this inference cant be derived from the first formula.
     
  6. Mar 1, 2015 #5

    Bystander

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    Think again. What is "v?"
     
  7. Mar 1, 2015 #6

    Suraj M

    User Avatar
    Gold Member

    That would be if F is a constant.
    Can you specify a situation!!
     
  8. Mar 1, 2015 #7
    V is the velocity. But I didnt understand your point.
     
  9. Mar 1, 2015 #8

    Bystander

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    What is "v" in terms of "r?"
     
  10. Mar 2, 2015 #9
    V is velocity which is distance/time. So you mean to say that the distance or the radius in this case is more so the velocity is more at the edge. So the Centripetal Force is more. Is this what you meant to tell me?
     
  11. Mar 2, 2015 #10

    Bystander

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    In your original question, you've ignored the fact that v equals omega times r and when looking at the dependence of centripetal acceleration on r.
     
  12. Mar 2, 2015 #11
    I'm tryng to interpretate the law: in the first equation the force, that deviate the particle along the orbit, increases together with the speed if we fix the radius, and it decreases together with the radius if we fix the speed.
    In the second equation the force increases togheter with the radius, because fixing the angolar speed and increasing the radius, the speed (not explicit here) must increase and then also the force.
     
  13. Mar 2, 2015 #12
    I said badly "it decreases together with the radius" but I would say "the force decreases when the radius increases in the first equation" (if we fix the speed).

    I hope that I can convince you there isn't a paradox about the force vs radius that sometime it increases, and sometime it decreases: it's enough that you fix one of the indipendent variabiles and then you'll se how the force changes when at the same time also the other variabile changes.

    In other words, if we fix the angular speed, we know that the periferic speed increases when the radius increases and so the force. But if we fix the periferic speed, the angular speed decreases if the radius increases and then the force decreases.

    I'm italian and I don't use to write in english but if I see anything that it's named physics it may be that I could try to speak japanese too.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Centripetal Acceleration.
Loading...