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Centripetal Accleration

  1. Oct 21, 2014 #1
    How would you go about proving that centripetal F=(mv^2)/r by diagramming and solving for the magnitude of the forces in the x and y direction?

    For example, suppose I wanted to calculate the work done in the radial direction by centripetal force.
  2. jcsd
  3. Oct 22, 2014 #2


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  4. Oct 22, 2014 #3
    Thanks so much! Really helpful
  5. Oct 22, 2014 #4
    Work is the product of the applied force magnitude x the magnitude of the displacement (D) in the same direction as the applied force. As a result, this is sometimes expressed as W = F x Dcosθ where θ is the angle between the two vectors (F and D). Since the F and D vectors are always perpendicular for circular motion of a mass at a constant speed, the angle between the two vectors is always 90°. So, the work done in circular motion at constant speed is 0 since cos90° is 0.
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