Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Homework Help
Introductory Physics Homework Help
Centripetal Force at an Angle
Reply to thread
Message
[QUOTE="bfr, post: 1605964, member: 79748"] [b][SOLVED] Centripetal Force at an Angle[/b] [h2]Homework Statement [/h2] The design of a new road includes a straight stretch that is horizontal and flat but that suddenly dips down a steep hill at 22 degrees. The transition should be rounded with what minimum radius so that cars traveling 90 km/h will not leave the road? [h2]Homework Equations[/h2] v=(2*pi*R)/T F=ma a=(v^2)/R [h2]The Attempt at a Solution[/h2] 90 km/hr=25 m/s. I tried setting up an equation where the centripetal force equaled the force of gravity:(25^2)/r=9.8 sin 22 , but that gives me a radius of approximately 170.25m, when the correct answer is 63.8m. EDIT: Solved. (25^2)/r=9.8 [/QUOTE]
Insert quotes…
Post reply
Forums
Homework Help
Introductory Physics Homework Help
Centripetal Force at an Angle
Back
Top