(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An amusement park ride consits of a rotating vertical cylinder with rough canvas walls. After the rider has entered and the cylinder is rotating sufficiently fast, the floor is dropped down, yet the rider does not slide down, The rider has a mass of 50 kilograms, the radius R of the cylinder is 5 meters, the angular velocity of the cylinder when rotating is 2 radians per second, and the coefficient of static friction between the rider and the wall of the cylinder is 0.6.

(b) Calculate the centripetal force on the rider when the cylinder and state what provides that force.

(c) Calculate the upward force that keeps the rider from falling when the floor is dropped down and state what provides that force.

(d) At the same rotational speed would a rider of twice the mass slide down the wall? Explain you answer.

2. Relevant equations

F=m*a

a=R*w^2

3. The attempt at a solution

I could derive the centripetal force by applying newton's second law and the formula for centripetal aceleration. I got 1000 N but i am not sure of my answer. And I dont understand very well what force is involved in pulling up the person when the floor is dropped down and how is friction involved.

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# Centripetal Force of an amusement park ride

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