Centripetal Force of merry-go-round

nautica

a) A 22 kg child is riding a merry-go-round that is rotating at 40 rpm. What centripetal Force must she exert to stay on if she is 1.25 m from its center???

40 rpm = 4.19 rad/s
r = 1.25 m

Ac = (4.19 rad/s)^2 * (1.25 m) = 21.95 m/s^2

F = (22 kg) * ( 21.95 m/s^2) = 482.9 N

b) What cent Force does she need to stay on one that rotates at 3 rpm if she is 8 m from its center

3 rpm = .314 rad/s

Ac = (.314 rad/s)^2 (8 m) = .789 m/s^2

Force = (22 kg) (.789 m/s^2) = 17.36 N

c) compare each force with her weight.

Force 1 is 21.95 x's her weight
Force 2 is .789 x's her weight

how does this look
thank
nautica

Related Introductory Physics Homework Help News on Phys.org

HallsofIvy

Homework Helper
Looks good to me.

Cool, thanks

Nautica

PrudensOptimus

This is the wrong forum. This should be posted in K12 section not College.

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