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Centripetal force plot

  1. Mar 23, 2010 #1

    kso

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    1. The problem statement, all variables and given/known data
    what are the units of the slope of a velocity^2 vs. centripetal force plot? and why should the line pass through the origin?


    2. Relevant equations



    3. The attempt at a solution
    I'm getting m/km for units but I'm not sure what that actually means so I don't know why it should go through the origin of the graph.
     
    Last edited: Mar 23, 2010
  2. jcsd
  3. Mar 23, 2010 #2
    Welcome to the forum!

    According first to the relevant equations we got the following:

    Centripetal Force = [tex]\frac{mass * velocity^2}{radius}[/tex]

    By this we deduce that such a slope of velocity would lead us to be:

    m =[tex]\frac{mass}{radius}[/tex]

    That is mainly due because we have set up the Centripetal Force to be the Y axis and the velocity square in the X one.

    Hope that helped, you may try now work out the math to see why does it pass through the origin.
     
  4. Mar 23, 2010 #3

    kso

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    Thank you! That helped a lot. :)
     
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