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Centripetal Force Problem: Determine Vehicle Speed and Forces | 1988M1 Homework
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[QUOTE="Mister T, post: 5252631, member: 572021"] The force [I]m[/I][B]g[/B] points downward. A component of it, [I]mg[/I] sin 15°, points down the hill. Your intuition is that it must play some role? Well, it does. It plays the same role it would play if the car were moving either up or down the hill. But as far as the car moving a horizontal direction, it plays no role. Again, if the car were moving up or down the hill, the friction force would oppose that motion. So if the car starts to drift up the hill, a friction force would act down the hill to oppose that motion. If the car is spiraling outward we wouldn't say it's moving away from the center! As long as its path is concave towards the center we would say, for purposes of describing how it's instantaneous direction is changing, we would say it's moving towards the center. Think of centripetal as a direction, not a force. If the car's path is concave inward, there is an inward [I]net[/I] force. In the same way the path of a projectile is concave downwards because there is a downward [I]net[/I] force. [/QUOTE]
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Centripetal Force Problem: Determine Vehicle Speed and Forces | 1988M1 Homework
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