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Centripetal force

  1. Jul 27, 2009 #1
    1. The problem statement, all variables and given/known data
    A 1.00 x10^3 kg car is moving through a flat curve on a road at a velocity of 30.0 m/s. If the coefficient of friction between the road and the tires is 0.600, the radius of the curve is


    2. Relevant equations
    r=v^2/(coefficitent of friction)(g), r=mv^2/F


    3. The attempt at a solution
    I tried two ways so solve this question, but im not sure which was is correct.
    the first thing i did was, find F by multiplying 9.81m/s2 and the mass (1000). then plugging that into the r=v^2/f. Then i used the first formula i provided above and just plugged all the variables in (excluding mass). Does the mass need to somehow be in there?
     
  2. jcsd
  3. Jul 27, 2009 #2

    diazona

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    In [itex]r = mv^2/F[/itex], the force should be the centripetal force that holds the car in the curve, not the weight of the car.
     
  4. Jul 27, 2009 #3
    so 30^2 divided by 0.600 times 9.81m/s2 giving me 153m, would be the correct answer?
     
  5. Jul 27, 2009 #4

    diazona

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    Yep, that's it. But you should make sure you get the same answer both ways.
     
  6. Jul 27, 2009 #5
    Alrite. thank you =)
     
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