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Centripetal force~

  1. Feb 14, 2015 #1
    if the centripetal force can be only provided by normal contact force.

    centripetal velocity is Vs. If V<Vs, then it will lose contact of the road?
    Or it will lose contact when n=0? Or when n<0?

  2. jcsd
  3. Feb 14, 2015 #2


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    What are V and n?
    Is this homework?
  4. Feb 15, 2015 #3
    no it is not

    v is just the velocity of the object and n is the normal force

    i m just confusing on this concept
  5. Feb 15, 2015 #4


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    On a flat road, the normal force cannot act as the centripetal force.
  6. Feb 15, 2015 #5
    i mean at a road that have inclination
  7. Feb 15, 2015 #6


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    In order for the normal force to be a centripetal force, the vehicle would need to be moving in a path that curves up away from the surface. If the road is flat, that means that the vehicle would need to lift off the road, even if the road were flat, but inclined.

    ["Flat" as A.T. intended it means that the road must stay in a single plane. In other words, it cannot curve vertically]
  8. Feb 15, 2015 #7


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    Draw yourself a free-body (i.e. force) diagram for a car on an inclined, curved road. If the situation is what I think it is, there should be 3 forces: gravitational, normal force, and frictional force.

    Any force that has a component toward or away from the center of the circular path contributes to the centripetal force.
  9. Feb 15, 2015 #8
    By this, do you mean that the road is banked?

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