1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Centripetal motion

  1. Feb 12, 2006 #1
    resolved thanks to astronuc... radius = d/2

    i accidentally used the diameter as my radius
     
    Last edited: Feb 12, 2006
  2. jcsd
  3. Feb 12, 2006 #2

    Astronuc

    User Avatar

    Staff: Mentor

    Well, let the period T = 1/f = 4.4 s.

    and f = [itex]\omega[/itex] /2[itex]\pi[/itex]

    and the centripetal force = Fc = m[itex]\omega^2[/itex]r = mv2/r, where r is the radius of the circular trajectory.

    Also don't forget the rider is still in a gravitational field, so don't forget the rider's weight due to gravity, mg, which is always down.

    See references on circular motion - http://hyperphysics.phy-astr.gsu.edu/hbase/circ.html#circ
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Centripetal motion
  1. Centripetal Motion (Replies: 2)

  2. Centripetal motion (Replies: 8)

  3. Centripetal Motion (Replies: 1)

  4. Centripetal Motion (Replies: 11)

  5. Centripetal Motion! (Replies: 2)

Loading...