1. The problem statement, all variables and given/known data At amusement parks, there is a popular ride where the floor of a rotating cylindrical room falls away, leaving the backs of the riders "plastered against the wall. Suppose the radius of the room is 3.30 m and the speed of the wall is 10.0 m/s when the floor falls away. What is the minimum coefficient of static friction that must exist between a rider's back and the wall, if the rider is to remain in place when the floor drops away if the rider has a mass of 55 kg? 2. Relevant equations Centripetal Force = mv^2/r = 1667 friction = u*Fn 3. The attempt at a solution centripetal force = friction = coefficient of friction * Normal Force Normal force = mg (weight) coefficient of friction = centripetal force/Normal Force = 51.5??? Is this correct?