The fast French train known as the TGV (Train a Grande Vitesse) has a scheduled average speed of 216 km/h. If the train goes around the a corner and the maximum acceleration experienced by the passengers is limited to 0.06 g, what is the smallest radius of curvature the track can have? 6.12Km b) What is the maximum speed the train can go around a curve of radius 0.9 km if train is not to exceed this acceleration limit? I dont know what I'm doing wrong for Part B. For part A i did the following: Vo/ Ac= radius 216/ (.06*g*60)= 6.12 km now I am trying to find just the speed or Vo which should be like the above but just altered to find the speed: Vo= Ac*radius Vo= (.06*g*60)*.9= 31.752 Km/hr...but thats not right. I then tried to put it into a ratio: 216/6.12= Vo/.9 and solved for Vo which i got as 31.764...very close to my orignal answer. PLEASE HELP!