# Centripital acceleration problem

• benji
In summary, the conversation discussed a kitchen gadget used for spinning lettuce to remove excess water. The radius of the container is 12cm and it rotates at 2.0 revolutions per second. The conversation then focused on finding the magnitude of the centripetal force at the outer wall, with equations and formulas being discussed. The final conclusion was to find the speed in m/s in order to calculate the centripetal acceleration.
benji
This is talking about one of those kitchen gadgets where you put the lettuce in the container and spin it so all of the water gets spun off.

The radius of the container is 12cm (0.012m). When the culinder is rotating at 2.0 revolutions per second, what is the magnitude of the centripital force at the outer wall?

What have you done so far?

I assume they want the magnitude of the centripetal acceleration. So, what's the formula for centripetal acceleration? (Check the book!)

All I've done so far is looked at equations and wrote down what I know:

Equations:
Fc=m(Ac)
Ac=(v^2)/r

What I know:
r=0.012m
rps=2.0
Fc=?

Well you have rev/sec. How much distance will an object go in one rev? When you figure that out, you can find the "tangential" speed in m/s, and then your formula might make more sense.

hey, 12cm is 0.12m.

acc= (v*v0) / r

cirumfrance = pi * 2 * 0.12 = 0.24pi

so v = (0.24pi * 2)/1 = 0.48pi

acc = 0.48pi / 0.12 = 4pi m/s*s

i think!

benji said:
All I've done so far is looked at equations and wrote down what I know:

Equations:
Fc=m(Ac)
Ac=(v^2)/r
That's the equation you want. To use it you have to figure out the speed.

What I know:
r=0.012m
Careful. 12 cm = 0.12 m, not 0.012 m.
rps=2.0
Fc=?
Now figure out the speed using v = distance/time. It goes 2 revolutions per second. Each revolution is the circumference of a circle: $c = 2 \pi r$. Figure out the speed in m/s.

Forget the centripetal force (since you are not given a mass); you want to find the centripetal acceleration.

Thanks guys, this helped a lot.

## 1. What is centripetal acceleration?

Centripetal acceleration is the acceleration that a body experiences when moving in a circular path. It is always directed towards the center of the circle and its magnitude is given by the formula a = v^2/r, where v is the velocity and r is the radius of the circle.

## 2. How is centripetal acceleration different from normal acceleration?

Normal acceleration, also known as tangential acceleration, is the component of acceleration that is perpendicular to the centripetal acceleration. Unlike centripetal acceleration, normal acceleration does not change the direction of the object's motion, but rather its speed.

## 3. What are some common examples of centripetal acceleration?

Some common examples of centripetal acceleration include the motion of a car around a circular track, the rotation of a Ferris wheel, and the orbit of a satellite around the Earth.

## 4. How is centripetal acceleration related to centripetal force?

Centripetal acceleration and centripetal force are directly related. According to Newton's second law of motion, force is equal to mass times acceleration (F = ma). In the case of centripetal motion, the force acting on the object is the centripetal force, which is provided by the centripetal acceleration.

## 5. How can I calculate centripetal acceleration?

To calculate centripetal acceleration, you need to know the object's velocity and the radius of its circular path. Once you have these values, you can use the formula a = v^2/r to find the centripetal acceleration. Alternatively, you can also use the formula a = ω^2r, where ω is the angular velocity of the object.

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