You plan to throw stones by using a sling of length 1.5 m which you whirl over your head. Suppose you wish to throw a stone a distance of 24 m. What must be the centripetal acceleration of the stone just before its release if it is to reach this distance? Assume that the release height is 3.0 m. So from this question, I was able to seperate the motion of the stone into x and y. Xf= X0+Vt Yf=Yi+Vt-gt^2 so putting them together I get t= (xf-x0)/vt yf=yi+V((xf-x0)/vt)-g((xf-x0)/vt)^2 Am I on the right track? I got an intial velocity of 10.2242. I'm not sure. I was told by my teacher to not worry about angles and other things like that.