1. The problem statement, all variables and given/known data An amusement park ride consists of a large vertical cylinder that spins about its axis fast enough that a person inside is stuck to the wall and does not slide down when the floor drops away. The acceleration of gravity is 9.8 m/s^2. Given g=9.8 m/s^2, the coefficient mu=.447 of static friction between a person and teh wall, and the radius of the cylinder R=4.8 m. For simplicity, neglect the persons depth and assume he or she is just a physical point on the wall. The persons speed is v=2(pi)r/T, where T is the rotation period of the cylinder (the time to complete a full circle) Find the maximum rotation period T of the cylinder which would prevent a 74 kg person from falling down. Answer in units of s. 2. Relevant equations A=v^2/r v=2(pi)r/T 3. The attempt at a solution i set sum of the forces in the y direction equal to Fn=Fg, since the person is not moving in the y direction thus able to find Fn, i plugged that into the formula Fs= (mu)s(Fn), and got 324.1644. Then i did the sum of the forces in the x directoin, which i had as Fs=mv^2/r, thus i found v^2, and plugged v into the v formula to get T. I think i am missing centripital force in my x direction, but i dont know how to represent it, and get a number for it. Please respond with explanation, and answer will be also greatly appreciated.