Wondering if I did this right. Find the centroid of the region shown , not by integration, but by locating the centroids of the rectangles and triangles and using additivity of moments.
I will give you the coordinates since I can't draw it.
For the rectangle (-1,0), (0,0) ,(-1,2), (0,2) and for the triangle I have (0,0), (2,0) and (0,2)
The Attempt at a Solution
So I did x Bar = M(triangle) + M(square) / (Area triangle + area square)
So to get M(triangle) I did xbar(area triangle) = (1)(4/2) = 2
I did this for the square too. I got (-1) When I plugged it into my above formula I got x bar = (1/3)
So, I did the same thing but with y. So I got y bar = 4/3
Does anyone agree? I pretty much did it like an example in class.