- #1

- 32

- 0

1. x=(2r sinθ)/3θ where x=r/2

2. r/2=(2r sinθ)/3θ

3. r=(4r sinθ)/3θ

4. 1=(4 sinθ)/3θ

5. 1/4= sinθ/3θ

6. 3θ/4= sin^-1(θ)

I don't know where to go from there. All I need is an expression in the form of θ= ...

Thanks!

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter francisg3
- Start date

- #1

- 32

- 0

1. x=(2r sinθ)/3θ where x=r/2

2. r/2=(2r sinθ)/3θ

3. r=(4r sinθ)/3θ

4. 1=(4 sinθ)/3θ

5. 1/4= sinθ/3θ

6. 3θ/4= sin^-1(θ)

I don't know where to go from there. All I need is an expression in the form of θ= ...

Thanks!

- #2

tiny-tim

Science Advisor

Homework Helper

- 25,832

- 251

(try using the X

1. x=(2r sinθ)/3θ where x=r/2

2. r/2=(2r sinθ)/3θ

3. r=(4r sinθ)/3θ

4. 1=(4 sinθ)/3θ

5. 1/4= sinθ/3θ

6. 3θ/4= sin^-1(θ)

I don't know where to go from there. All I need is an expression in the form of θ= ...

Thanks!

i'm confused …

6. has sin

were they

anyway, when you have A = sin

you can take sin of both sides, giving you sinA = B

- #3

HallsofIvy

Science Advisor

Homework Helper

- 41,833

- 963

Share: