- #1
Timiop2008
- 31
- 0
Hello everybody
I would also like to solve the following problem using either the Chain,Product, or Quotient Rule but am unsure of the working stages to get to the given answers
i) Find the equation of the tangent at the point with coordinates (1,1) to the curve with the equation y=(X2+3)/x+3
ii) Given that y=xe-3x find dy/dx and hence find the coordinates of the stationary points on the curve y=xe-3x
Again, help with the workings would be much appreciated.
Answers:
i) 4y=x+3
ii) (1-3x)e-3x , (1/3,1/3e-1)
I would also like to solve the following problem using either the Chain,Product, or Quotient Rule but am unsure of the working stages to get to the given answers
i) Find the equation of the tangent at the point with coordinates (1,1) to the curve with the equation y=(X2+3)/x+3
ii) Given that y=xe-3x find dy/dx and hence find the coordinates of the stationary points on the curve y=xe-3x
Again, help with the workings would be much appreciated.
Answers:
i) 4y=x+3
ii) (1-3x)e-3x , (1/3,1/3e-1)