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Question is

Find the derivative of F(x)= 3 sq rt of x^3-1

First step I did was changing the Sq RT to (x^3-1)^3/2

Then I solved it by 3/2(X^3-1)^1/2*3X^2

Another problem very similar

F(X)= 3 SQ RT of X^4+3x+2

Step 1 (X^4+3x+2)^3/2

Then 3/2(X^4+3x+2)*4x^3+3

I know how to do the derivatives my only concern is that 3 in front of the square roots are throwing me off, I just want to know if I'm doing it right.