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Chain rule difficulties, due tomorrow

  1. Oct 20, 2008 #1
    Chain rule difficulties, due tomorrow!!

    1. The problem statement, all variables and given/known data

    Find the derivative of

    y=e^square root of 1+tan(sinx)

    2. Relevant equations

    chain rule: F'(x)=f'(g(x)) * g'(x)


    3. The attempt at a solution

    I thought I had it and then while I was looking at other chain rules and started doubting my actual ability to sort out the chain rule...

    y=e^square root of 1+tan(sinx)

    y'=e^square root of 1+tan(sinx) *(1+tansinx)'

    y'=e^square root of 1+tan(sinx)* (0 +sec2sinx +cosx)

    Please help! My assignment is due tomorrow and I know there is something not quite right but I don't know why.
     
  2. jcsd
  3. Oct 20, 2008 #2
    Re: Chain rule difficulties, due tomorrow!!

    how would you evaluate these operations if you wanted to get a number out of them? Remember to take the chain rule in reverse of this order. For example, [tex]\frac{d[(x^{4})^3]}{dx} = 3(x^{4})^{2}*4x^{3}dx[/tex]

    ok LaTeX appears to be acting up. Basically you forgot to take the derivative of the square root *before* finding the derivative of what was inside it.
     
  4. Oct 20, 2008 #3
    Re: Chain rule difficulties, due tomorrow!!

    yikes I should probably work on my recopying skills. thank you very much!!
     
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