# Chain rule difficulties, due tomorrow

1. Oct 20, 2008

### susan__t

Chain rule difficulties, due tomorrow!!

1. The problem statement, all variables and given/known data

Find the derivative of

y=e^square root of 1+tan(sinx)

2. Relevant equations

chain rule: F'(x)=f'(g(x)) * g'(x)

3. The attempt at a solution

I thought I had it and then while I was looking at other chain rules and started doubting my actual ability to sort out the chain rule...

y=e^square root of 1+tan(sinx)

y'=e^square root of 1+tan(sinx) *(1+tansinx)'

y'=e^square root of 1+tan(sinx)* (0 +sec2sinx +cosx)

Please help! My assignment is due tomorrow and I know there is something not quite right but I don't know why.

2. Oct 20, 2008

### jhicks

Re: Chain rule difficulties, due tomorrow!!

how would you evaluate these operations if you wanted to get a number out of them? Remember to take the chain rule in reverse of this order. For example, $$\frac{d[(x^{4})^3]}{dx} = 3(x^{4})^{2}*4x^{3}dx$$

ok LaTeX appears to be acting up. Basically you forgot to take the derivative of the square root *before* finding the derivative of what was inside it.

3. Oct 20, 2008

### susan__t

Re: Chain rule difficulties, due tomorrow!!

yikes I should probably work on my recopying skills. thank you very much!!