[tex]y = ln[\sqrt(x^2+2)][/tex](adsbygoogle = window.adsbygoogle || []).push({});

I changed it to [tex] y = ln[(x^2+2)^{1/2}] [/tex]

I know the derivative of [tex]ln = \frac {1}{x}[/tex]

I'm not sure how to proceed.

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# Chain Rule Help

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