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Chain rule help

  1. Nov 5, 2009 #1
    Could someone explain this to me please where n=y/squareroot(4vt)

    ∂C/∂t=(dC/dn)(∂n/∂t)=-(1/2)(n/t)(dC/dn)

    When i take the derivative of 1/t^1/2 i get -(1/2)t^(-3/2) so where does the (-3/2) go to in the final answer of -(1/2)(n/t)(dC/dn). Thank you very much!!!
     
  2. jcsd
  3. Nov 5, 2009 #2

    LCKurtz

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    [tex] n = \frac y 2 v^{-\frac 1 2}t^{-\frac 1 2}[/tex]

    [tex]n_t = \frac y 2 v^{-\frac 1 2}(-\frac 1 2)t^{-\frac 3 2} = \frac y 2 v^{-\frac 1 2}t^{-\frac 1 2}(-\frac 1 2)t^{-1} = (-\frac 1 2)\frac n t[/tex]
     
  4. Nov 5, 2009 #3
    Thank you soooooo much!!!!
     
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