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Chain rule proof

  1. Aug 22, 2013 #1
    Is this proof of the chain rule valid ?

    Attached Files:

  2. jcsd
  3. Aug 22, 2013 #2
    How did you get this?
    Did you write this yourself?
  4. Aug 22, 2013 #3
    It's from a textbook...I just re-typed it into a word doc...
  5. Aug 22, 2013 #4
    Is it correct...I suspect there maybe some circular reasoning with the "error term" becoming 0 as h approaches 0.
  6. Aug 22, 2013 #5
    It looks valid to me, but just tell us why you do not trust your book. At which part.
  7. Aug 22, 2013 #6
    Can you explain to be the part on the bottom when we set g2=g(x+h) but E(g2) turns into E(g(x)) not E(g(x+h)) ?

    If that's valid, why is the limit as h approaches 0 of E(g(x)) is 0 ?
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