1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Chain rule

  1. Mar 9, 2010 #1
    1. The problem statement, all variables and given/known data
    n=y*sqrt((V)/(v*x) and Q=sqrt(v*V*x)*f(n)
    so i have V=-dQ/dx=(dQ/dn)*(dn/dx) and the final answer is V=(1/2)*sqrt((v*V)/x)(n*df/dn-f)

    2. Relevant equations



    3. The attempt at a solution
    i have tried diff. by hand and also by maple and cannot get the answer. What am i doing wrong, because after all i have to quantities added together and that seems weird to me.
     
  2. jcsd
  3. Mar 9, 2010 #2

    Mark44

    Staff: Mentor

    What exactly are you trying to do? Your problem statement gives two equations, but doesn't say what you are supposed to do with them or what you are supposed to find.

    Also, what's the significance of the underscore on v? You also show it italicized and bolded, which seems like overkill.
     
  4. Mar 9, 2010 #3
    n and Q are my equations that need to be differentiated. And i need to find V(x)=-dQ/dx=(dQ/dn)*(dn/dx), this differential is using similarity variables. For example when i take V(y)=dQ/dy=(dQ/dn)*(dn/dy), i get sqrt(v*x*V)*(df/dn)*sqrt(V/(v*x)), if you would like me to send you the file if you dont understand still, let me know.
    This problem deals with a boundary layer of a flat plate, V= velocity(at a distance infinity away from the plate) v(underscore)=kinematic viscosity, and V(x) and V(y) are the velocity profiles in the x and y direction that need to be found.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Chain rule
  1. Chain Rule! (Replies: 7)

  2. The chain rule (Replies: 2)

  3. Chain rule (Replies: 1)

  4. Chain rule (Replies: 2)

  5. Chain rule (Replies: 22)

Loading...