# Chair push Newtons Laws

• CallingAllCars7
In summary, a chair with a mass of 13.0 is being pushed with a force of 45.0 directed at an angle of 40.0 below the horizontal on a non-frictionless floor. The normal force can be found using the equation N = mg - Fsin(theta), where theta is the angle of the applied force. The normal force is directed upward and must be equal in magnitude to the downward forces acting on the chair in order to keep it from falling through the floor.

## Homework Statement

A chair of mass 13.0 is sitting on the horizontal floor; the floor is not frictionless. You push on the chair with a force = 45.0 that is directed at an angle of 40.0 below the horizontal and the chair slides along the floor.

[b]2. Homework Equations [/B]

These were given to me to help.
N= w-F1sin()
Fcos()=ma

## The Attempt at a Solution

with the equations given to me by the TA I thought that the answer would be 9.8*13-45sin(), but I keep getting the answer incorrect(my class uses masteringphysics for hw) and I even tried all sorts of other crazy equations.