The diagram shows a non uniform bar of mass 59kg suspended by light ropes. Calculate the force of tension in each rope and the distance between the left end of the bar and its center of gravity.
ΔT(torque) = 0
ΔFx = max
ΔFy = may
The Attempt at a Solution
First I wrote down all the variables that were given to me:
Mg (weight of the bar) = (59)(9.80) = 578.2N
M (mass of the bar) 59kg
g = 9.80 m/s(squared)
l1(lever arm 1) = 8.0m
I am unsure how to do this question because this question is on a worksheet full of questions where the mass or object is uniform. This question is the only question in the whole worksheet where the mass or object is not uniform thus (I guess) why its a "challenger" question.
Basically, could someone just show me how to find the distance "d" between the left end of the bar and its center of gravity because I am unsure as to how to even start out finding this.
Furthermore, to find the tension in each rope do you put the point of rotation at one of the ends where the ropes are, making the tension for that side zero then solve using the torque equation for the tension (of the other side). Then use the translational equilibrium equation to find out what the torque you set to the point of rotation was?
24 KB Views: 89