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Challenging problem for SHM.

  1. Sep 9, 2014 #1
    .

    Null
     

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    Last edited: Sep 10, 2014
  2. jcsd
  3. Sep 9, 2014 #2
    Disregard the tangent stuff on the right I tried doing something else...
     
  4. Sep 9, 2014 #3
    Any clues?
     
  5. Sep 10, 2014 #4

    ehild

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    I would be able to read your attempt if it was typed in.
    Such problems are solved by eliminating the unknown amplitude by using sin2(ωt)+cos2(ωt)=1

    ehild
     
  6. Sep 10, 2014 #5
    Yes,.
     
    Last edited: Sep 10, 2014
  7. Sep 10, 2014 #6
    By the way, you weren't to see my pictures? Mhm.
     
  8. Sep 10, 2014 #7

    ehild

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    You are supposed to type in your work. I can not decipher what you did from the pictures.

    Do the same you did when eliminating the amplitude, but eliminate omega this time.

    ehild.
     
  9. Sep 10, 2014 #8

    ehild

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    It is x=Asin(wt) and dx/dt= Aw cos (wt). The displacements and speeds are given at two different times.

    a=A sin(wt1) u/w=Acos(wt1) -->a2+( u/w)2=A2

    b=Asin(wt2) v/w=A cos(wt2) -->b2+( v/w)2=A2


    Eliminate the angular frequency this time.

    ehild.
     
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