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Challenging Qns On Work Energy Power

  1. May 25, 2006 #1
    hi i have a Qns.

    Dave jumps off a bridge with a bungee cord( a stretchable cord) tied around his ankle. He falls for 15m before the bungee cord begins to stretch. Dave's mass is 75kg and we assume the cord obeys Hook's law with elastic constant, k= 50N/m. if we neglect air resistance and the mass of the cord, calculate how far below the bridge Dave will fall before coming to a stop.

    i understand that i have to use the formula F=Ke and i need to find F.
    how should i go about finding it? which formula to use?
     
  2. jcsd
  3. May 25, 2006 #2

    Doc Al

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    Staff: Mentor

    Consider conservation of energy.
     
  4. May 25, 2006 #3
    Got it!

    Let X be the height Dave fall before comin to a stop
    Let e be the extension of bungee cord.

    GPE=mgh
    =(75)(9.82)(X)

    Elastic Potential Energy= 1/2Ke^2
    = 1/2(50)(X-15)^2

    Equate it together and X = 55m.

    However can't u sovle by finding Force??
     
  5. May 25, 2006 #4

    Doc Al

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    Staff: Mentor

    There's no direct way to use F=ke to solve for e (if that's what you mean), since both F and e are unknowns.
     
  6. May 25, 2006 #5

    Andrew Mason

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    You are indirectly using force when you use energy. The incremental potential energy stored in the cord is dU = Fde, so total potential energy is:

    [tex]U = \int_{0}^{e_f}Fde = \int_{0}^{e_f}Kede = \frac{1}{2}Ke_f^2[/tex]

    [Note: Ke is spring constant x extension, not Kinetic energy]

    AM
     
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