1. The problem statement, all variables and given/known data An electron is fired at a speed vo = 5.0 106 m/s and at an angle o = -44° between two parallel conducting plates that are D = 3.7 mm apart, as in Figure P16.66. The voltage difference between the plates is V = 100 V. (a) Determine how close, d, the electron will get to the bottom plate. 2. Relevant equations Conservation of energy: (1/2)mv^2 = -qEd E=V/D 3. The attempt at a solution I was thinking conservation of energy because the electron is initially moving and when it reaches max, it stops and KE is converted to PE. (1/2)(9.109e-31)[(5e6)sin(44)]^2 = (-1.602e-19)(27027.02)(d) d = 0.001269 m E = (100/0.0037) = 27027.2 N/C Anyone knows what is wrong?