Chandelier tension

  • Thread starter Amria
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  • #1
Amria
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Homework Statement



A chandelier with mass m is attached to the ceiling of a large concert hall by two cables. Because the ceiling is covered with intricate architectural decorations (not indicated in the figure, which uses a humbler depiction), the workers who hung the chandelier couldn't attach the cables to the ceiling directly above the chandelier. Instead, they attached the cables to the ceiling near the walls. Cable 1 has tension T_1 and makes an angle of theta_1 with the ceiling. Cable 2 has tension T_2 and makes an angle of theta_2 with the ceiling.

Find an expression for T1 that does not include T2

Homework Equations


I have found that the

Sum of the forces of in the x direction is T2cos(theta2) - T1cos(theta1) = 0

Sum of the forces in the y direction is T1sin(theta1) + T2sin(theta2) - mg = 0

The Attempt at a Solution



from the first equation, T2= T1cos(theta1)/cos(theta2)

would then T1sin(theta1) + T1cos(theta1)/cos(theta2)*sin(theta2) - mg = 0?
Any ideas how to solve algebraicly for T1?
 

Answers and Replies

  • #2
hage567
Homework Helper
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To start, isolate the T1 terms on one side of your equation. That might make things a bit clearer.
 
  • #4
Physkid101
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yes. T1sin(theta1) + T1cos((theta1)/cos(theta2))*sin(theta2) - mg = 0...then u factor out the T1 and u should be able to do it on ur own from there.
 

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