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Change in angle gives change in one side of triangle

  1. Nov 2, 2011 #1
    i wonder about this assignment number 3.10.54:


    they solve it with derivation:


    I tried to solve it like this:

    [tex]x=tan^{-1}(\frac{tan75\cdot 30\cdot0,96}{30})=74,4048[/tex]

    75-74,4048=0,5952 too much error in angle compared to answer sheet

    [tex]x=tan^{-1}(\frac{tan75\cdot 30\cdot1,04}{30})=75,5523[/tex]

    75,5523-75=0,5523 angle error under value in answer sheet

    I dont get this: how come 1,04 of original height gives smaller max error in angle so that by adding that angleerror from the answer one would exceed the assignment of 4 percent of error in height because:

    [tex]\frac{tan75,57\cdot 30}{tan75\cdot 30}=1,0413[/tex]
    Last edited: Nov 2, 2011
  2. jcsd
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