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Change in entropy of an irreversible adiabatic process
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[QUOTE="Chestermiller, post: 6464321, member: 345636"] I agree with your calculated internal energy change. For an enthalpy change, I get 1.4 times as much, or -2123 J. The next step is to determine the final temperature. You know the internal energy change, the number of moles of gas, and the heat capacity of the gas. From that, you can determine ΔT. What value do you get, and what do you get for the final temperature. You can get the final pressure P2 knowing the final temperature and employing the ideal gas law, or from the enthalpy change, since you know ΔU, P1, V1, and V2. The values you get from both these methods should agree. [/QUOTE]
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Change in entropy of an irreversible adiabatic process
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