# Change in Entropy

## Homework Statement

Find the change in entropy when 2.00 kg of water at 100 degrees C is boiled away to steam at 100 degrees C. Give your answer in kJ/K

## Homework Equations

deltaS=Q/T
Q=m*Lvaporization

## The Attempt at a Solution

Q=m*Lvaporization
Q=2 kg * 22.6*10^5 J/kg
Q = 4.52x10^6 J

I'm not not sure how to find T though since it's at 100 degrees and going to 100 degrees...

Thanks!

There's a good deal of views on here, does no one know how to do this? ;)

Andrew Mason
T is given. All you have to do is put it in the correct scale. The denominator in $\Delta Q/T$ is the absolute temperature at which the heat flows into the water.