1. The problem statement, all variables and given/known data An 8.5 g ice cube at -10°C is put into a Thermos flask containing 200 cm3 of water at 20°C. By how much has the entropy of the cube-water system changed when equilibrium is reached? The specific heat of ice is 2220 J/kg·K. Cw= 4190 Mi= 8.5 Mw= 200 Lf= 333000 Ci=2220 2. Relevant equations Tf=cw*mw(20)-mi(lf+10ci)/mw*cw+mi*cw Tf= 288.73 K mi*ci*ln(273.15/263.15)+lf*mi/273.15+mi*cw*ln(288.73/273.15)+mw*cw*ln(288.73/293.15) 3. The attempt at a solution .70366+10.36+1.975-6.365 I got 6.67 J/k. But I'm not sure thats right.