2NOCl(g) <--> 2NO(g) +Cl2(g)[/B]
What will be the effect on equilibrium concentration of NOCL when equal moles of NOCL and NO are introduced in the mixture at constant temperature?
Kconcentration = [NO]2[Cl2] / [NOCl]2
The Attempt at a Solution
In my opinion, the concentration of NOCl will decrease because the number of moles of chlorine is less than the new equilibrium concentration and so NOCl will decompose to give more chlorine.