I have a test tomorrow and I've tried this problem a million times and it won't come out! I got it right when I turned it in, but I cannot for the life of me remember what I did! Help!(adsbygoogle = window.adsbygoogle || []).push({});

1. The problem statement, all variables and given/known data

A manometer using oil (density 0.86 g/cm^3) as a fluid is connected to an air tank. Suddenly the pressure in the tank increases by 0.83 cm Hg.

a) How much does the fluid level rise in the side of the manometer that is open to the atmosphere?

b) What would your answer be if the manometer used mercury (density = 13.6 g/cm^3) instead?

2. Relevant equations

P_{2}= P_{1}+ [tex]\rho[/tex]gh

3. The attempt at a solution

I've tried a couple of ways:

[tex]\rho[/tex]gh = P_{2}- P_{1}

Assuming that P_{1}is atmospheric pressure, so = 10^5 Pa

(0.00086 kg)(9.8 m/s)(h) = (0.00086)(9.8 m/s)(0.0083 kg/m^2*) - 10^5

= -1.19 e7 m so -1.19 e5 cm? definitely very wrong.

*not sure about this conversion

I kind of remember using the mercury with the equation at some point, so I tried playing with that but it didn't come out then, either. Also, I think the gravity is supposed to cancel out somewhere.

P_{Hg}= (13.6 g/cm^{3})(9.8 m/s)(h) = P_{oil}= (0.86)(9.8)(0.83)

Gravity cancels out, so

13.6h = (0.86)(0.83)

h = 19.05 m

Then I thought maybe I could plug that in somewhere, but I can't figure out where.

I'm frustrated and freaking out. Help!

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Change in fluid levels in a manometer given a pressure change

Can you offer guidance or do you also need help?

Draft saved
Draft deleted

**Physics Forums | Science Articles, Homework Help, Discussion**