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## Homework Statement

## Homework Equations

ΔKE=W+FcosΘd

KE=.5mv^2

Final Vel^2=initial Velocity^2+2ax

## The Attempt at a Solution

So calculate the force at x=2.6 to -5.356N, set 2.6(-5.356)=1.3Vf^2-1.3(0^2) which seemed to prove a problem as the square of the final velocity was negative, but just used that negative square in the difference of kinetic energy equation and got -5.356 J- 0= -5.356 as the change in Kinetic energy or work. I am skeptical of my methods and also a little clueless on the second part of the problem.

Many thanks