- #1

mopar969

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Take 100g aluminum cup at 25 degrees celcius and 200g of water (h2o) at 25 degrees celcius and add 20 g ice at -10 degrees celcius. Stir.

What is the final state of the system?

Here is what I have done:

I used the equation delta Q= (mcup)(Ccup)(delta T cup)+(mh2o)(Ch20)(delta T h20) + (m ice)(Cice)(delta T ice). And for my final answer I got 23.49 degrees celcius

Is this answer correct and is this all that the question is asking for?