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Change of KE in Ballistic Pendulum Collision

  1. Nov 16, 2009 #1
    1. The problem statement, all variables and given/known data
    2ch2ka1.jpg

    2. Relevant equations
    mv=(m+M)v'
    KEi=1/2mv2
    PE=KE (after collision)

    3. The attempt at a solution
    I'm am particularly stuck on part C although I'm not very confident in my first two answers either.

    a)
    1/2(m+M)vf2=(M+M)gh
    vf2=2gh
    vf=SQRT(2gh)

    mv=(m+M)vf
    v=((m+M)SQRT(2gh))/m

    b)
    KEi=m(m+M)22gh)
    -------------------
    2m2

    KEf=1/2(M+m)2gh

    deltaKE=1/2(M+m)2gh - m(m+M)22gh)
    -------------------
    2m2

    stuck...

    Thanks for any help in advance.
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
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