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Ok, need refresher b4 finals!!!

Change order of integration

[tex]\int_{-2}^0\int_0^{\sqrt{4-x^2}}f(x,y)dydx[/tex]

to

[tex]\int_0^2\int_{-\sqrt{4-y^2}}^0f(x,y)dxdy[/tex] going from right to left, and the fact that my original integral is the part of the circle in quadrant 2, it should be [tex]x=-\sqrt{4-y^2}[/tex]

or

[tex]\int_0^2\int_0^{\sqrt{4-y^2}}f(x,y)dxdy[/tex] this is my original answer, but now i'm thinking it's the 1st one :-\

Change order of integration

[tex]\int_{-2}^0\int_0^{\sqrt{4-x^2}}f(x,y)dydx[/tex]

to

[tex]\int_0^2\int_{-\sqrt{4-y^2}}^0f(x,y)dxdy[/tex] going from right to left, and the fact that my original integral is the part of the circle in quadrant 2, it should be [tex]x=-\sqrt{4-y^2}[/tex]

or

[tex]\int_0^2\int_0^{\sqrt{4-y^2}}f(x,y)dxdy[/tex] this is my original answer, but now i'm thinking it's the 1st one :-\

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