Let R be the elliptical regin in the first quadrant by x^2/3^2+y^2/2^2=1. x=3u, y=2v, evaluate the area of R. How do I setup the double integral? By this I mean what do I put in for f(g(u,v),h(u,v))jacobian dudv? I know the bounds of u and v and the Jacobian but I not sure what to do for g and h. Would that be just pluging 3u and 2v into x^2 and y^2, respectively? But what happens to the 1 in the eqaution? So by solving the (u,v) cordinates, one comes up with (0,0); (1,0); and (0,1). The Jacobian is 6.