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## Homework Statement

Given

\int{0}{3} \int{0}{sqrt{(9-z^2)}} \int{0}{sqrt{(9-y^2-z^2)}} dx dy dz

express the integral as an equivalent in dz dy dx

## Homework Equations

## The Attempt at a Solution

From the origial limits z goes from 0 to when x^2 + y^2 <= 9

For dz I have

\int{0}{ sqrt(-x^2-y^2+9)} dz

Is this right so far?