# Change to polar help

1. Oct 20, 2007

### Qyzren

http://img187.imageshack.us/my.php?image=polargy3.jpg

3. The attempt at a solution
http://img484.imageshack.us/my.php?image=picture155jy1.jpg
i get an extra cos² thi term!! WHY!!
am i doing the substitution completely wrong?? or i forgot/left something out which i can not seem to see!

Thank you

2. Oct 21, 2007

### Gib Z

4th line, $dw_1= -w\sin \phi d\phi$ unfortunately :(

3. Oct 21, 2007

### Qyzren

oops, i meant to write dw1 = cos thi dw.
nevermind, i got it.
I have to use Jacobian matrix instead of what i did.

Last edited: Oct 21, 2007