Switch the order of integration:
∫∫f(x,y) dydx, with 0≤x≤π/2, 0≤y≤sin(x)
The Attempt at a Solution
∫∫f(x,y) dxdy, with sin(x)≤x≤π/2, 0≤y≤sin(x)
The upper bound of x is π/2, while the lower bound is sin(x). It's just the first 1/4 of the area of a sine wave. The upper bound of y is sin(x) and lower bound is 0.
I was just wondering if someone could confirm. I've been having a bit of trouble with integrals and assigning regions. Thank you :)