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I have the following sum:

[tex]\displaystyle{\sum_{n=1}^\infty}(-1)^n\frac{(2z)^n}{(2n)!}[/tex]

and I wanna let it run from n=0 to infty

it´s somehow obvious that:

[tex]\displaystyle{\sum_{n=0}^\infty}(-1)^n\frac{(2z)^n}{(2n)!} - 1=\displaystyle{\sum_{n=1}^\infty}(-1)^n\frac{(2z)^n}{(2n)!}[/tex]

but how do I prove it? I tried to write n-1 instead n but when I calculated it it wasn´t in a way the result from the equation above.

Does anyone know how I should do this operation?

thanks in advance

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# Changing the running parameter

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