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Changing to polar integration

  1. Nov 4, 2013 #1
    1. The problem statement, all variables and given/known data
    Evaluate the integral by changing to polar coordinates.

    Double Integral: (x^2+y^2)dydx, where dy is bound between 0 and (4-x^2)^(1/2) and dx is between and -2 and 2


    3. The attempt at a solution
    okay so I can turn this into
    Double Integral: (r^2)rdrdθ

    My question is on the parameters of dr and dθ
    I really want to say dr goes from 0 to 2.
    does dθ go from 0 to 2∏
     
  2. jcsd
  3. Nov 4, 2013 #2

    Simon Bridge

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    If that is what you really want to say, then what is stopping you?

    note:
    it is not dr that goes from 0 to 2, it is r that does that. etc.
     
  4. Nov 4, 2013 #3

    Mark44

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    Can you describe, in words, the region over integration takes place? If you understand this region, you'll pretty much have answered your question about θ.
     
  5. Nov 4, 2013 #4

    LCKurtz

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    I second Mark's comment. Tell us what the region looks like. For all we know, your original integral may be set up wrong.
     
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