- #1
MathematicalPhysicist
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Homework Statement
I am reading the solutions manual of Srednicki's textbook in QFT (alongside reading the textbook itself).
Here it is:
http://www.scribd.com/doc/87916496/Srednicki-Ms-Qft-Solutions-Rev
So the equation that he arrives at (6.27).
I am not sure I understand how did he arrive at the RHS?
I mean if I write the exponent down, i.e [tex] e^{-(q_2-q_1)^2/(2c)} e^{-(q_1-q_0)^2/(2c)}[/tex]
then I get:
[tex]-[(q_2-q_1)^2/2c + (q_1 -q_0)^2/2c] = -[\frac{(q_2-q_0)^2}{4c} +\frac{2q_1^2-2q_1(q_2+q_0)+q_2q_0}{2c}[/tex]
Now to get the RHS we need to assume that: [tex]q_2q_0 - 2q_1(q_2+q_0)=0[/tex] which I don't see it written in the textbook, perhaps I skipped over it...
Is it written in the book?