Hey guys, I'm kind of stuck on how to do this one. Positive charge Q is distributed uniformly along the x-axis from x=0 to x=a. A positive point charge q is located on the positive x-axis at x=a+r, a distance r to the right of the end of Q. (a) Calculate the x- and y- components of the electric field produced by the charge distribution Q at points on the positive x-axis where x>a. (b) Calculate the force (magnitude and direction) that the charge distribution Q exerts on q. (c) Show if r>>a, the magnitude of the force in part (b) is approximately Qq/4pi(epsilon)r^2. Explain why this result is obtained. Alright, I'm having trouble getting started. First off, I understand that the y components is 0, no need to go there. I know that since the charge is distributed, I have to use an integral. the Limits of the integral are from (0,a) But what how exactly is the integral? (I'm going to use k instead of 1/4piepsilon To my understanding.... E=kq/r^2 So, dE=kdq/r^2 How would I go from there? (if that were correct...) Thanks!