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Charge in a box

  1. Sep 13, 2007 #1
    2 infinite boards placed in space in x =5 and x = -5, charged with unformed positive density [tex]\sigma[/tex] , between those boards is a spacial distribution of charge [tex]\rho[/tex] given: [tex]\rho[/tex](x,y,z)=Ax^2 , A const.

    There is no charge outside the boards.

    I need to calculate the charge in a box with a side=4, located in (0,0,0) parallel to axis.

    I want to approach it using gauss. For this I need to find the flom through the box.

    My first question:
    Does the fields generated by the boards effect the box or they negate each other and only the spacial field effects?
     
  2. jcsd
  3. Sep 13, 2007 #2

    learningphysics

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    This just seems to be a straight integration problem... integrate charge density over the volume to get the charge... you don't need the flux...
     
  4. Sep 13, 2007 #3
    Ok, no flux.
    What about my qustion, do I skip the fields from boards?
     
  5. Sep 13, 2007 #4

    Doc Al

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    All you need to do is find the total charge within the box. No need to worry about fields from outside (or inside!) the box. Are the boards in the box? If not, their charges don't count.
     
  6. Sep 13, 2007 #5
    The integral is from 0 to 4?
     
  7. Sep 13, 2007 #6

    Doc Al

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    That depends on where the box is located. If it extends from (0,0,0) to (4,4,4), then yes.
     
  8. Sep 13, 2007 #7
    Actually it's center in (0,0,0) so my integral should be from -2 to 2?
     
  9. Sep 13, 2007 #8

    Doc Al

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    That sounds right to me.
     
  10. Sep 13, 2007 #9
    I get this:
    [tex]\int_{-2} ^{2}(64Ax^2)[/tex]

    But the answer is:
    [tex]\frac{256A}{3}[/tex]
     
  11. Sep 13, 2007 #10

    learningphysics

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    Your integrand is wrong. can you show how you got that integral?
     
    Last edited: Sep 13, 2007
  12. Sep 13, 2007 #11
    you mean 64? volume of box.... side=4....
     
  13. Sep 13, 2007 #12
    the integrand is Q.
    [tex]\rho[/tex](v) = [tex]\frac{dq}{dv}[/tex]
     
    Last edited: Sep 13, 2007
  14. Sep 13, 2007 #13

    learningphysics

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    Take a slice at a particular x... the volume of the slice is 4*4*dx... so what's the charge contained in this slice...
     
  15. Sep 13, 2007 #14
    GOT IT.
    Thanks again.
     
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