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Introductory Physics Homework Help
Charge of 2 conducting spheres separated by a distance
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[QUOTE="jolly_math, post: 6856680, member: 729008"] [B]Homework Statement:[/B] Two identical conducting spheres of radius 15.0 cm are separated by a distance of 10.0 m. What is the charge on each sphere if the potential of one is +1500 V and the other is -1500 V? Take V = 0 at infinity. [B]Relevant Equations:[/B] V = E∆s V = kq/r First assuming only one sphere at a potential of 1500 V, the charge would be q = 4πεrV = 4π(8.85×10 [SUP]−12[/SUP]C[SUP]2[/SUP]/N · m)(0.150 m)(1500 V) = 2.50×10[SUP]−8[/SUP]C. The potential from the sphere at a distance of 10.0 m would be V =(1500V)(0.150m)/(10.0m) =22.5V. I don't understand the reasoning of the following: This is small compared to 1500V, so we will treat it as a perturbation. This means that we can assume that the spheres have charges of q = 4πεrV = 4π(8.85×10[SUP]−12[/SUP]C[SUP]2[/SUP]/N · m)(0.150 m)(1500 V + 22.5 V) = 2.54×10[SUP]−8[/SUP]C. What does the perturbation refer to, and how is 1500 V + 22.5 V related to the specific distance 0.150 m? Thank you. [/QUOTE]
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Charge of 2 conducting spheres separated by a distance
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